Problem
The sum of the squares of the first ten natural numbers is,
12 + 22 + … + 102 = 385 The square of the sum of the first ten natural numbers is,
(1 + 2 + … + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
Sol. 1
#include <stdio.h>
int main(void)
{
int number = 100;
int sum = 0, result1 = 0, result2 = 0;
for (int i = 1; i <= number; i++) {
sum += i;
result1 += i * i;
}
result2 = sum * sum;
printf("%d", result2 - result1);
}